When three coins are tossed what is the probability of getting at least one head and one tail?

When three coins are tossed what is the probability of getting at least one head and one tail?

34
∴ The probability of getting at least one head and a tail is 34.

What is the probability of getting at least one head and one tail?

∴ P ( getting at least one head, one tail) =68 =34 .

When three coins are tossed simultaneously What is the probability of getting one head?

3/8
n(E3) = 3. Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8. and, therefore, n(E4) = 7. Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8.

When three coins are tossed together?

READ ALSO:   How do you show that a decimal is infinite?

Solution: When 3 coins are tossed, the possible outcomes are HHH, TTT, HTT, THT, TTH, THH, HTH, HHT. (i) Let E1 denotes the event of getting all tails. Hence the required probability is ⅛.

What is the probability of getting 1 head in 3 coin tosses?

0.88 is the probability of getting 1 Head in 3 tosses. Exactly 1 head in 3 Coin Flips The ratio of successful events A = 3 to total number of possible combinations of sample space S = 8 is the probability of 1 head in 3 coin tosses.

What is the probability of getting exactly 1 tail in 3 tosses?

Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 1 tail, if a coin is tossed three times or 3 coins tossed together. 0.38 is the probability of getting exactly 1 Tail in 3 tosses.

What is the probability of flipping three coins and getting one tail?

There are 8 total possible outcomes for flipping three coins, and 3 of the 8 scenarios have one tail in them (THH, HTH, HHT). The answer is 3/8. Originally Answered: If three coins are tossed simultaneously, what is the probability of getting exactly one tail?

READ ALSO:   How to be attractive if you re ugly?

What are the possible outcomes of tossing 3 coins?

The possible outcomes of tossing 3 coins are { (HHT), or (TTH) or (HHH) or (THT) or (THH) or (HTH) or (HTT) or (TTT)} The probability of getting at least one head = number of possibilities of heads as outcome/total no of possibilities = 3/8