What is the probability of obtaining 2 tails?

What is the probability of obtaining 2 tails?

The probability of tossing the same coin again and resulting in tails is 0.5 because the two tossing events are completely independent of each other. Therefore, the probability of tossing a coin two times a getting two tails is 0.5 x 0.5 or 0.25.

When a fair coin is tossed 9 times?

When a coin is tossed 9 times the probability of getting exactly six heads is obtained with the help of Bernoulli trials. The probability of getting exactly six heads is 21/128.

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What’s the probability of even heads outcome if I throw 9 coins?

The number of all possible outcomes is 512 thus the probability to get even number of heads is 0.5.

How many times should you toss a coin if you want a probability of ST least .9 of getting heads at least once?

So, coin must be tossed at least 4 times so that probablity of having at least one head is more than 90\%.

What is the probability of getting a sum 9 from two throws of dice?

1/9
What is the probability that sum on both faces is 9 when two dice are thrown simultaneously? So, P(sum of 9) = 1/9.

What is the probability of getting exactly 2 tails when 3 coins are tossed together?

So the probability of getting at most 2 tails is 7/8.

How many times must submit toss a fair coin?

A man must have to toss a fair coin 3 times.

What is the probability of getting sum of 9?

So, P(sum of 9) = 1/9.

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What is the probability of two fair coins being tossed simultaneously?

Question: Two fair coins are tossed simultaneously. What is the probability of getting only one head? Solution: When 2 coins are tossed, the possible outcomes can be {HH, TT, HT, TH}. Thus, the total number of possible outcomes = 4. Getting only one head includes {HT, TH} outcomes. So number of desired outcomes = 2.

What is the probability of getting exactly one tail on a coin?

On tossing a coin twice, the possible outcomes are {HH, TT, HT, TH} Therefore, the total number of outcomes is 4. Getting only one tail includes {HT, TH} Therefore, the number of favorable outcomes is 2. Hence, the probability of getting exactly one tail is 2/4 = 1/2. 1/2.

What is the probability of getting 5 heads in 8 tosses?

A fair coin is tossed 8 times find the probability that it shows heads exactly 5 times. On a given toss (a Bernoulli trial), p= P (head) = 1/2 and q =P (tail) =1−p = 1/2. The probability of getting exactly five heads in eight tosses is obtained using the binomial probability formula P (n−k)

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How many possible outcomes can be obtained from 9 coin tosses?

There would be 9 coin tosses and each toss could possibly result to only 2 possible outcomes – a head or a tail. The total number of outcomes is obtained by applying the fundamental counting principle.