Table of Contents
- 1 At what height g becomes half?
- 2 What is the value of g at a height h r?
- 3 At what height above the earth’s surface will the value of ‘` g `’ be zero?
- 4 At what height value of g is 1 4?
- 5 What is the value of G at height R and depth R?
- 6 At which height value of G will be g 4?
- 7 How is the value of g Class 9 calculated?
- 8 What is the change in the value of G with height?
- 9 Does H=R/2 imply g’ =0 at H = R/2?
At what height g becomes half?
If we use 6,371 km as Earth’s radius, the distance above the surface where gravitational acceleration is halved would be 2,639 km.
What is the value of g at a height h r?
4g
The value of gravitational acceleration ‘g’ at a height ‘h’ above the earth’s surface is 4g then (R = radius of earth)
At what height above the earth’s surface will the value of ‘` g `’ be zero?
Near the surface of the Earth (sea level), gravity decreases with height such that linear extrapolation would give zero gravity at a height of one half of the Earth’s radius – (9.8 m. s−2 per 3,200 km.)
At what altitude above the earth’s surface is the acceleration due to gravity equal to g 7?
Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2….The Value of g Depends on Location.
| Location | Distance from Earth’s center (m) | Value of g (m/s2) |
|---|---|---|
| 50000 km above surface | 5.64 x 107 m | 0.13 |
At what height g becomes g 4?
At height R the value of g becomes 1/4 to that on the earth.
At what height value of g is 1 4?
“g'” is gravitational acceleration at height H from surface of the earth. The height above the surface when the acceleration due to gravity will be 1/4th of its value on the surface of earth is equal to “r”(radius of the earth).
What is the value of G at height R and depth R?
| Acceleration Due to Gravity (g) | |
|---|---|
| Symbol | g |
| Formula | g = GM/r2 |
| Values of g in SI | 9.806 ms-2 |
| Values of g in CGS | 980 cm s-2 |
At which height value of G will be g 4?
At what height above earth’s surface is the value of g is half of its surface on earth given its radius 6400 km?
∴ At a height of 2649.6 km from the Earth’s surface, the acceleration due to gravity will be half its value on the surface.
At what height above the surface of earth is the value of g decreases by 1 percent?
Thus at a height, h=0⋅005RE the acceleration due to gravity reduces by 1\%.
How is the value of g Class 9 calculated?
Calculate acceleration due to gravity earth
- G is the universal gravitational constant, G = 6.674×10-11m3kg-1s-2.
- M is the mass of the massive body measured using kg.
- R is the radius of the massive body measured using m.
- g is the acceleration due to gravity measured using m/s2.
What is the change in the value of G with height?
So as altitude h increases, the value of acceleration due to gravity falls. This describes the variation of g with height or altitude. What is the change in the value of g at a height h? g1 = g (1 – 2h/R) This g1 gives the formula for g at height h. So the value of g will decrease by this amount: 2hg/R, at a height h above the earth’s surface.
Does H=R/2 imply g’ =0 at H = R/2?
You can see that it does not imply g’ =0 at h=R/2. And for h =R we get g’ = g/4 as we should. If you take the exact equation and expand 1/ (R+h)^2 in a Taylor series, and keep terms only up to the first power of r/R, you will get the equation that you wrote above.
How do you find acceleration due to gravity at different heights?
Variation of g with height: As altitude or height h increases above the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g1 = g (1 – 2h/R). Here g1 is the acceleration due to gravity at a height of h with respect to the earth’s surface and R is the radius of the earth.
How do you find the dependence of G on H?
The equation you wrote for the dependence of g on h is an approximation. It is valid only when h is much smaller than R. You can see that it does not imply g’ =0 at h=R/2. And for h =R we get g’ = g/4 as we should.