Sage-Tips

What is the expression for distance covered in Nth second for uniformly accelerated motion?

Answer: s= u+ a/2(n+1). Explanation: this distance ‘s’ is travelled in n seconds.

How do you find the distance in uniformly accelerated motion?

The distance, then, for uniformly accelerating motion can be found by multiplying the average velocity by the time. We know that the final velocity for constantly accelerated motion can be found by multiplying the acceleration times time and adding the result to the initial velocity, vf=vi+at.

What is the formula to find distance covered?

The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.

What is the formula of displacement of the uniformly accelerated body during nth second its initial velocity is Vo and acceleration is A?

Its initial velocity is v, and acceleration is a. (1) S = vo + (2n – 1) 5- Vonttal (2) S = (2n – 1) (3) S = von + a(2n – 1) (4) S = vo + 5 (2n – 1) 2.

How do you find the distance in the fifth second?

The distance covered in 5 seconds is the distance from the second 0 to the second 5. The distance covered in the 5th second is the distance covered from the second 4 to the second 5, i.e. in one second.

How do you find distance traveled in 5 seconds?

1. 8 \% B.
2. 12 \% C.
3. 25 \% D.
4. 36 \% Medium. Solution. Verified by Toppr. D.
5. 36 \% The correct option is D. Given, A free falling body. Distance traveled in 5s. S=ut+21​gt2 since u=0,g=10m/s. =21​×10×52. =125m. Distance travelled in 5^th sis: Distance travelled in 5s- Distance travelled in 4s. Distance travelled in 4s=21​×10×42. =80m. So,

What is distance covered in Nth second?

The distance travelled by a body in the nth second is given by the expression (2 + 3n).

How do you calculate the distance from the last second?

These equations are, v = u + at. Where, S is the distance and u is the initial speed of an object, v is the final speed of an object, and a is the acceleration and t is time.

What is distance covered?

Distance Covered represents the total distance covered by a defender from the time the bat makes contact with the ball until the moment he fields it. This metric only takes into account the route actually traveled by the fielder — NOT the direct route from the fielder’s starting position to the ball.

What is the simple formula of distance?

Learn how to find the distance between two points by using the distance formula, which is an application of the Pythagorean theorem. We can rewrite the Pythagorean theorem as d=√((x_2-x_1)²+(y_2-y_1)²) to find the distance between any two points.

How do you find the distance in the nth second?

What is formula of displacement in Nth second?

Final equation for displacement in the nth second is. s = u + 1/2a(2n-1)

How to find distance travelled by an uniformly accelerated body?

Formula to find distance travelled by an uniformly accelerated body is The distance x covered by a body moving in a straight line in time t is given by the relation- 2x²+3x=t If v is the velocity of body at a certain instance of time, find it’s acceleration. eg. v = 2x ; assume t = 0 ; x = 2 m ; find a (t)?

How to derive a relation for the distance travelled in nth second?

Home » Forum » Modern Physics » kinematicshow to derivea relation for the distance travelled in nth second by a uniformly accelerated body7 years agoAnswers : (3)distance travelled in n seconds:S1= un + 1/2a (n^2)distance travelled in (n-1) seconds:S2 = u (n-1) + 1/2a ( (n-1)^2)distance travelled in nth second:S1-S2= u + 1/2a (2n-1)

How do you find the nth velocity of a moving particle?

Uniformly accelerated motion creates a AP ( arithmetic progression) because velocity of the particle is increasing every second with a equal constant amount called common difference in AP. So, to find nth velocity of the body just use AP’s formula for finding nth term. And for distance multiple that nth velocity with nth value of time.

How do you find the acceleration of a moving body?

The distance x covered by a body moving in a straight line in time t is given by the relation- 2x²+3x=t If v is the velocity of body at a certain instance of time, find it’s acceleration. eg. v = 2x ; assume t = 0 ; x = 2 m ; find a (t)?