How many grams of Al2O3 can be formed theoretically?

How many grams of Al2O3 can be formed theoretically?

30.4 g O2 will produce 64.6 g Al2O3 . The limiting reagent is aluminum, and the maximum amount of aluminum oxide that can be produced in this reaction is 57.4 g .

How many moles of Al2O3 will be formed?

The number of moles of Al2O3 formed is approximately 4.25 moles.

How many moles of aluminum oxide are produced when one mole of aluminum reacts with excess oxygen?

1 Expert Answer Looking at the balanced equation, we see the mol ratio of Al to Al2O3 is 4 : 2 or 2 : 1 and so the moles of Al2O3 formed will be 1/2 the moles of Al used, i.e. 1/2 x 24.2 = 12.1 moles.

READ ALSO:   Can I study abroad after HSC?

How many moles of al2o3 are produced when 3.7 moles of aluminum react completely?

After you cancel out the units of measurement to check the order of the conversion, multiply 3.7 with 4 and then divide the answer by 2 . You get 7.4 moles of Al .

What is the molar mass for al2o3?

101.96 g/molAluminium oxide / Molar mass

What happens when Al reacts with o2?

Aluminum also reacts with oxygen to form aluminum oxide.

Does Al react with o2?

Aluminium will burn in oxygen with a brilliant white flame to form the trioxide alumnium(III) oxide, Al2O3.

How many mole of oygen react with aluminium to give Al2O3?

2 mole of Al2O3. 3 mole of O2 reacts with 4 mole of aluminium to give =2 mole of Al2O3. Hence 0.78 mole of oygen react with Aluminium to give 0.52 mole of Al2O3. Hope you Got it. Have a Good Day !!!

What happens when aluminium reacts with 32g of oxygen?

READ ALSO:   What happens if you super glue a cut?

We have only 5.4g of aluminium whereas 32g of oxygen is available. Hence aluminium is the limiting agent. (32g — 4.8g) of oxygen will remain unreacted. Answer :- when 5.4 g of aluminium reacts with 32g of oxygen 0.1 mole of Al2O3 will be formed.

What is the limiting reactant of Al?

Al is the limiting reactant as there is not sufficient of it to react with excess oxygen, as from the equation 1 mole of Al forms half mole of aluminium oxide, the molar mass of aluminium oxide is 27*2 + 16*3 = 102 How many moles of oxygen are required to react completely with 14.8 mol Al?

What is the molar mass of aluminium oxide formed from Al and oxygen?

Al is the limiting reactant as there is not sufficient of it to react with excess oxygen, as from the equation 1 mole of Al forms half mole of aluminium oxide, the molar mass of aluminium oxide is 27*2 + 16*3 = 102. Hence mass of Aluminium oxide formed = 102/2=51 g.

READ ALSO:   Should you separate analog and digital ground?