Sage-Tips

What is the volume of oxygen liberated when 49gm of potassium chloride is decomposed at STP?

×12.25 =3.36 L.

What volume of oxygen at STP will be obtained by the action of heat on 20g of kclo3?

molar volume of o2 at stp =22.4L….from(2×123.5) gms of kclo3, volume of o2 obtained=(3×22.4) L,from 20gm of kclo3, volume of o2 obtained=3×22.4×20÷(2×123.5) litres………

What is the volume of oxygen at STP liberated when 12.25 gram of potassium chlorate is subjected to heating?

= 3.36 L of O2 of STP.

What volume of oxygen is obtained when 10.0 g of potassium chlorate is decomposed at STP?

Approx. 3L of dioxygen gas will be evolved.

What is the volume of oxygen obtained at STP?

5×224002×22400×200=500 mL.

What volume of oxygen at STP will be?

× 22.4L = 11.2L.

What is the volume of O2 required at STP?

O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters. 1.5625 × 22.4 = 35 liters.

What volume of oxygen will be produced by heating 245 kg of pure kclo3 at STP?

or 245 g of KClO2 produce O2 = 3 x 22.4 lits.

What volume of oxygen gas is released at STP?

The volume that is occupied by 1 mol of an ideal gas at STP, which is 22.4 L. What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

What volume of oxygen is needed at STP?

You’d need 6.55 L of oxygen at STP to form that much water. STP conditions, which are defined as a pressure of 100 kPa and a temperature of 273.15 K, should immediately get you thinking about molar volume of a gas. More specifically, about the fact that 1 mole of any ideal gas occupies exactly 22.7 L at STP.

What volume of oxygen at STP is required to affect the combustion of 11 Litres of ethylene?

8.25 litres
What volume of oxygen at STP is required to affect the combustion of 11 litres of ethylene at 273°C and 380 mm of Hg pressure? Answer in my book : 8.25 litres.

What is the volume in Litres of oxygen at STP required for complete combustion of 32g of CH4?

Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole. If ​1 mole of CH4 requires 2 moles of O2 for complete combustion. Therefore 1/4 ​mole of CH4 will requires = 1/4 2 moles of O2 = 0.5 mol of O2 for complete combustion. So 11.2 L of O2 is required for complete combustion of 4 g CH4.

What volume of oxygen at STP can be produced by potassium chlorate?

What volume of oxygen at STP can be produced by 6.125 g of potassium chlorate according to the reaction? = 0.05 moles. Therefore B is the correct option. Was this answer helpful? , and then filtering to remove the solid, leaving soluble impurities in solution. Any NaHCO 3 that remains in the solution is not recovered. The solubility of NaHCO 3

What gas is produced when kcio3 decomposes?

When potassium chlorate (KCIO3) is decomposed, oxygen gas and potassium chloride are produced. What volume of oxygen gas at STP is produced when 4.72 g of KCIO3 decomposes?

How to calculate the volume of oxygen at STP?

To calculate the volume of oxygen at STP use the unit-factor method. The fact that 1 mol of any ideal gas at STP occupies a volume of 22.414L is well known. This ratio simply becomes one more conversion factor in the solution. 4.72g ……………. …………..?

What volume of nitrogen gas is required to cover 1g of silica?

Its percentage strength is nearly The volume of Nitrogen gas at 1 atm and 273 K required to cover 1 gr of silica gel is 0. 1 2 9 d m 3 .Calculate the surface area of the gel if each N 2 ​ molecule occupies an area of 1 6. 2 × 1 0 2 8 M 2. 2 0 ml alkyne ( C 2 ​ H 2 ​) is hydrogenated by 4 0 ml of hydrogen gas to from alkane ( C 2 ​ H 6 ​).