What is the probability of flipping a coin 7 times?
1 in 128
With seven flips, we have 128 possibilities, with only one of these possibilities being a successful one (T-T-T-T-T-T-T). Thus, the probability of flipping seven tails in a row in seven flips is 1 in 128.
What is the probability of flipping 2 heads in 3 flips?
1/2
Answer: If you flip a coin 3 times, the probability of getting at least 2 heads is 1/2.
What is the probability of flipping?
When we flip a coin a very large number of times, we find that we get half heads, and half tails. We conclude that the probability to flip a head is 1/2, and the probability to flip a tail is 1/2.
What is the probability of getting Htht?
So probability of getting head and tail one by one is 2/2^n = 1/2^n-1.
What is the probability of getting exactly 2 heads when tossing a coin price?
The probability of getting two heads on two coin tosses is 0.5 x 0.5 or 0.25. A visual representation of the toss of two coins.
How do you calculate the HT sequence on LHS?
The first term on LHS is if we get a T on a our first flip (with probability 1 2 ). The second term is if we get a H (heads) on our first flip (with probability 1 2 ), which means that we are effectively starting over with 1 extra flip. Now let Y be the random variable which counts the number of flips till we get a HT sequence.
What is the expected value of HH/TT until the first flip?
By manipulating an equation based on the result of the first flip, shown at this link: the answer is 6. This also makes sense intuitively since the expected value of the number flips until HH or TT is 3. But is there a way to tackle this problem by summing a series of probabilities multiplied by the values?
Does it take longer to see the first HH than HT?
So we should expect that it takes longer on average to see the first HH than to see the first HT. An interesting exercise would be to ask: is there a biased coin of some kind for which the expected number of flips to see HH is the same as the expected number of flips to see HT?
What is the total probability of completing the first HT on tossn?
If the first HT is completed on toss n, then m = n − 2, and there are n − 1 possibilities for the initial string, each occurring with probability ( 1 2) n − 2, assuming a fair coin. The total probability of completing the first HT on toss n is therefore ( n − 1) ( 1 2) n, and you want