Sage-Tips

How do you find the number of elements greater smaller than an element in an array?

The simplest trick is sort the array first and count the number of elements in the array. So for example if you have 10 elements then your first element is less than 9 and likewise the second element is smaller than 8 and so on.

How do I find the nearest smaller element in an array?

A Simple Solution is to use two nested loops. The outer loop starts from second element, the inner loop goes to all elements on left side of the element picked by outer loop and stops as soon as it finds a smaller element.

How many elements there is a strictly smaller element and a strictly greater element?

only 2 have a strictly smaller and strictly greater element, 1 and 3 respectively.

How do I count the number of two numbers between values in C++?

Approach used in the below program is as follows

1. Input an array let’s say, int arr[]
2. Calculate the length of both the arrays using the length() function that will return an integer value as per the elements in an array.
3. Start the loop from i to 0 till i less than size of an array.

How do you find the number in an unsorted array?

Front and Back Search in unsorted array

1. Initialize indexes front and back pointing to first and last element respectively of the array.
2. If front is greater than rear, return false.
3. Check the element x at front and rear index.
4. If element x is found return true.
5. Else increment front and decrement rear and go to step 2.

How do you find the largest and smallest number in an unsorted integer array in CPP?

The program output is shown below.

1. #include
2. using namespace std;
3. int main ()
4. {
5. int arr[10], n, i, max, min;
6. cout << “Enter the size of the array : “;
7. cin >> n;
8. cout << “Enter the elements of the array : “;

How do you find the kth smallest element in the unsorted list?

Algorithm to find the Kth smallest element in an unsorted array

1. Input the number of elements of the array.
2. Input the Kth element to be found.
3. Input the elements of the array.
4. Sort the array.
5. Return the arr[k-1].

How do you find the kth largest element in an unsorted array in Java?

If we sort the array in ascending order, the kth element of an array will be the kth smallest element. To find the kth largest element, we can pass k= length(Array) – k.

How do you find the sum of the nearest smaller and greater numbers?

Algorithm

1. Initialize two variables just_greater and just_smaller with some very large and small value respectively.
2. Loop through the array as: If the array element is greater than x but smaller than just_greater then just_greater = arr[i]
3. Print Sum of nearest smaller and greater number.

How do you find the nearest number in an array?

Find k closest numbers in an unsorted array

1. Make a max heap of differences with first k elements.
2. For every element starting from (k+1)-th element, do following. ….. a) Find difference of current element with x. …..
3. Finally the heap has k closest elements.

How to search through an unsorted array in JavaScript?

Searching through an unsorted array looks like a simple task – we just iterate through the array and return an element index as soon as the match is found. Alternatively, if end of array is reached, failure status is returned. Here is the pseudocode of the function: Now that we have the straight-forward solution, we can think of some improvements.

How to find the last element in an array with O(n)?

A simple solution is to perform linear search. The linear search algorithm always results in worst case complexity of O (n) when element to be searched is last element in the array. Front and Back search algorithm for finding element with value x works the following way:

How to count all distinct elements in an unsorted array?

Given an unsorted array, count all distinct elements in it. Examples: Input : arr[] = {10, 20, 20, 10, 30, 10} Output : 3 There are three distinct elements 10, 20 and 30.

How do you sort an array with distinct elements?

A simple solution is to run two loops. For every element, check if it has appeared before. If yes, increment count of distinct elements. Time Complexity of above solution is O (n 2 ). We can Use Sorting to solve the problem in O (nLogn) time. The idea is simple, first sort the array so that all occurrences of every element become consecutive.