Table of Contents
- 1 Which type of reaction is this H2 Br2 2hbr?
- 2 What will be the enthalpy change for the following reaction H2 Br2?
- 3 What decomposes to H2 and Br2?
- 4 What is the order of the reaction H2 Br2 gives to HBr?
- 5 What is the Molecularity of the reaction H2 Br2 gives to HBR?
- 6 What is the following order of reaction Br2 2br?
- 7 What does 2 in front of HBr mean in this equation?
Which type of reaction is this H2 Br2 2hbr?
redox reaction
So, this is a redox reaction.
What will be the enthalpy change for the following reaction H2 Br2?
H2 + B.E. Br2 ] – 2 B.E. HBr = 435 + 192 – 2 × 364 = – 101 kJ.
What is the rate law for H2 Br2 2HBr?
The rate law is dtdx=k[H2]1/2[Br2]1/2: On increasing the concentration of Br2 four times, by how much times the rate of reaction will change?
Which of the following is a redox reaction H2 Br2?
The reaction H2 + Br2 → 2HBr is a redox reaction. As H2 has an oxidation state of zero and Br2 also has zero oxidation state. Hence , both oxidation and reduction is taking place simultaneously. It is a redox reaction.
What decomposes to H2 and Br2?
The compound HBr can be decomposed to form H2 and Br2.
What is the order of the reaction H2 Br2 gives to HBr?
The molecularity of the reaction H2+Br2→2 HBr is 2. Reason. The order of the reaction is 3/2.
What is the enthalpy change for h2 G br2 G h2 g3 g2g HBr G h3 g8 g3 moles Moleivively?
Therefore, the enthalpy change for this reaction is -101 kJ.
When the enthalpy of the products is greater than the enthalpy of the reactants the reaction?
exothermic reaction
In an exothermic reaction, the total enthalpy of products is greater than that of reactants.
What is the Molecularity of the reaction H2 Br2 gives to HBR?
The molecularity of the reaction H2 + Br2 → 2HBr is 2.
What is the following order of reaction Br2 2br?
The order of the reaction is 23 and it is determined experimentally.
What is the rate of reaction between H2(G) and Br(G)?
For the reaction H2 (g) + Br2 (g) → 2HBr (g), the experimental data suggest , rate = k [Hz] [Br_]^1/2. The molecularity and order of the reaction are respectively O 2, 3/2 O 3/2, 3/2 O 1,1 O 1,1/2
Why are there 2 HBR molecules in H2 and Br2?
The 2 in H2 and Br2 means there are 2 H atoms, in nature H never exists as a single atom. I think in this case thinking about this visually rather than mathematically helps a lot. The 2 hydrogen atoms get broken up in the reaction and individually bind to each Br atom due to the valence electrons, therefor 2 HBr molecules form.
What does 2 in front of HBr mean in this equation?
It means the same thing. The 2 infront of HBR means that that hole expressions is multiplied by two, so two hydrogens, and two bromines. Instead of writing 2 hydrogens and 2 bromines, you can just right two infront of the whole expression, rendering the equation complete.