How many grams of oxygen are needed to combust 20.0 grams of propane C3H8 )? Use the reaction below to answer the question?

How many grams of oxygen are needed to combust 20.0 grams of propane C3H8 )? Use the reaction below to answer the question?

How many grams of Oxygen are needed to combust 20 grams of propane? Answer: 72.6 g of oxygen are needed to burn 20 g of propane.

How many grams of CO2 are in C3H8?

[note: 1g of C3H8 produced exactly 3g of CO2. So 20 g of C3H8 will produce (20 x 3)= 60 g of CO2.

How many moles of CO2 are produced from a mole of C3H8?

3 moles
Every one mole of C3H8 propane will react with 5 moles of O2 to yield or produce 3 moles of Carbon dioxide CO2 and 4 moles of H2O water.

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What is the mole ratio of C3H8 to H2O?

Next look at the stoichiometric ratio of water to propane (C3H8), which is 4:1 based on the coefficients. That means that for every one mole of propane used, four moles of water are created. Therefore, if we need to make 0.5944 moles of H2O, we will need a quarter of that for propane, or 0.1486 moles C3H8.

How many moles are in 28g of iron?

We know that, molar mass of an element is the atomic mass in grams. Hence, molar mass of iron is 56g. Thus, 0. 5 mole is present in 28g of iron.

What is the balanced equation for C3H8 O2?

There will be 10 oxygens on the products side and 2 on the reactants so to balance these out, we multiply the 02 on the reactants side by 5. The final equation will be C3H8 + 502 —-> 3CO2 + 4H20.

How many moles of CO2 are produced from 5 moles O2?

1 Expert Answer If we consume 5mol O2, then we produce 5mol CO2.

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What is the mole ratio for C3H8 and O2?

The mole ratio is a fraction made from the coefficients in the balanced equation. We use the mole ratio to convert the number of moles or molecules of one substance to the number of moles or molecules of another substance. The mole ratio would be either 1 molecule C3H85 molecules O2 or 5 molecules O21 molecule C3H8 .

How many oxygen atoms are present in 2.50 moles of oxygen atoms?

Therefore there are 3.0×1024 3.0 × 10 24 oxygen atoms.

How many moles are in 607 grams of Argon?

To solve this let us find out the molar mass of Argon, it is 39.948 g/mol or roughly 40 g /mol. It means that one mole of Argon weighs 40g. 607g / 40g moles or 15.175 moles.