How many 128 8 RAM chips are required to design a 2048 byte memory how many address lines are required to implement 2048 bytes of memory?

How many 128 8 RAM chips are required to design a 2048 byte memory how many address lines are required to implement 2048 bytes of memory?

How many 128 × 8 RAM chips are needed to provide a memory capacity of 2048 bytes?…Subscribe to GO Classes for GATE CSE 2022.

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What is 8K memory?

RAM with 8K memory can store 8192 bytes or 65536 bits. Therefore : 8192 bytes = 8 * 8192 bits =65536 bits.

How many 1024 * 1 RAM chips are required to construct a 1024 * 12 memory system?

Q. How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system?
C. 8
D. 12
Answer» c. 8
Explanation: one 1024 * 1 ram chips is of 1-bit. so, for construction of 1024 * 8 ram chip of 8-bits,
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How many 128 * 8 RAM chips are needed to provide a memory capacity of 2048 bytes?

Since 8 bits = 1 byte, Each RAM chip has 64 x 1 byte = 64 bytes. Thus the number of chips to address a memory capacity of 2048 bytes will be, 2048/64 = 32 chips….Subscribe to GO Classes for GATE CSE 2022.

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What will be the address range of 2048 * 8?

It’s organized as x8 (bytes), which means there are only 256 unique addresses, as the question states. 2^n=256, where n is the number of address lines required, so 8 address bits are needed. That’s 256 memory locations.

Which material is used to make a memory chip?

Memory chips consist primarily of silicon, which is obtained from sand. The process of making sand into silicon involves melting, cutting, polishing and grinding.

What is a RAM chipset?

A RAM chip is a microchip used as RAM storage for computers and other devices. This is the actual chip that is soldered onto small circuit boards in order to create RAM cards or sticks, and it is rated for performance and capacity differently, depending on the model and manufacturer.

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How many address bits are needed for a 1024 in 8 memory?

Or 1024*8 gives 8192, or 2^13. so 13 bits. If it ain’t a 1024 bits multiplied by 8 bits, or there are 1024 arrays of each size of 8 bit, then 1024 arrays, so 10 bits of addresses will do it.

How many 128 * 8 memory chips are needed to provide the memory of capacity?

Since 8 bits = 1 byte, Each RAM chip has 64 x 1 byte = 64 bytes. Thus the number of chips to address a memory capacity of 2048 bytes will be, 2048/64 = 32 chips….Subscribe to GO Classes for GATE CSE 2022.

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