How do we connect three resistance Each of 6 ohm to get total resistance I 2 ohm II 9 Ohm?

How do we connect three resistance Each of 6 ohm to get total resistance I 2 ohm II 9 Ohm?

Answer: To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a parallel circuit and one in series. In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances.

How would you join 3/6 ohms to get 4 ohms?

The third 6 Ω resistor is in series with 3 Ω. Hence, the net resistance of the circuit is 6 Ω + 3 Ω = 9 Ω. ∴ the total resistance is 4 Ω.

What is the total resistance if 3 resistance of 4 ohms 6 ohms and 8 ohms respectively are connected in parallel?

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Minimum resistance is obtained by connecting all three resistances in parallel => 1/R =1/4+1/6+1/8 =>1/R = 6/24+4/24+3/24 => 1/R = 13/24 => R =24/13 ohm . Hope it helps you.

How three resistances 2ohm 3 ohm and 6 ohm be connected to give a total resistance of 4 ohm?

To obtain a total resistance of 4 Ω from three resistors of given resistances, Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω.

What is the resistance of three 6 ohm resistors in parallel?

Three 6-Ω resistors placed in parallel would provide a resistance which is equivalent to one 2-Ω resistor.

What is the total resistance of two resistance of 4 ohm and 6 ohm are connected in parallel?

Hence , Total resistance for series combination is 10Ω

What is the total resistance if three resistance of 3 ohm are connected in series?

When P,Q and R are connected in parallel, their total resistance is 3Ω. When P and Q are connected in parallel their total resistance is 10/3 Ω. When P and R is connected in series, their total resistance is 15 Ω.

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What is the equivalent resistance if 2ohm 3ohm and 4ohm are connected in parallel combinations?

Three resistors 2 ohm, 3 ohm and 4 ohm are connected so that the equivalent resistance is 9 ohm The resistors are connected e all in series all in paralel.

How will you connect three resistors of resistance 2 ohm 3 ohm and 5 ohm?

To get the resistance of 2.5 Î , we will have to connect the resistors of values 2 Î and 3 Î in series and this arrangement should be connected in parallel with the resistor of value 5 Î .

What is the total resistance if 6 ohms and 3 ohms resistors are connected in series in a circuit *?

The total resistance of the circuit is 3+6=9…

What is the resistance of three 6 Ω resistors connected in series?

18-Ω
The presence of three 6-Ω resistors in series would be equivalent to having one 18-Ω resistor in the circuit. And the presence of four 6-Ω resistors in series would be equivalent to having one 24-Ω resistor in the circuit.

How will you connect three 3-ohm resistors to get an effective resistance?

How will you connect three 3-ohm resistors, one 4-ohm resistor, one 5-ohm resistance, and one 6-ohm resistor to get an effective resistance between 8 and 9 ohms? Connect three 3 ohm resistance in parallel. This gives you effective resistance of 1 ohm. Connect 4 and 6 ohm in parallel. This gives you effective resistance of 2.4 ohm.

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How do you find the equivalent resistance of 6 ohms?

To get an equivalent resistance of 6 ohms, we have to use both parallel and series connection in the circuit. First, the two resistors are connected in parallel to obtain a combined resistance of 2 ohms and then the combined resistance in connected in series with the third resistor to give a total resistance of 6 ohms.

What is the resistance of the resistor 2+4 in series?

= 2 ohms and this is added with the resistance of the third resistor in series as 2+4= 6 ohms. Was this answer helpful?

How do you find the total resistance of a circuit?

To obtain a total resistance of 4 Ω from three resistors of given resistances, Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω.