Sage-Tips

What will be the velocity of object thrown upward with 40m s after 2s?

So, the final velocity of the ball after 2 seconds will be $20m/s$ will be in the upwards direction. Hence, option B is the correct option. Note: Both velocity and acceleration are vector quantities.

How long it would take a body to reach maximum height if it is thrown with a velocity of 49m S?

1) The maximum height to which it rises. 2) The total time it takes to return to the surface of the earth. Let us consider the time is t to reach the maximum height H. (2) The total time ball takes to return to the surface of the earth = 5 + 5 = 10 sec.

How long does it take for the ball to reach its highest point?

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or 2 minutes and 56 seconds, until the cannonball destroys the cannon that fired it.

What would be the velocity of a stone thrown upwards and reach its highest point?

zero
The velocity is zero because the stone is at stationary at the highest point in its trajectory.

What is the least velocity at which a ball can be thrown through a distance 40m?

5ms−1.

When a stone is thrown directly upwards with initial velocity of 30.0 m/s what will be the maximum height it will reach and when will it be?

Time taken by stone to rise to its maximum height is T=ug=3010=3 sec.

What is the initial velocity of the ball thrown vertically upwards?

A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth. Initial velocity of the ball (u) = 49m/s.

How do you calculate the initial velocity of a stone thrown up?

S0 is the displacement of the body projected upwards and S1 as the displacement of the body dropped when they both meet. S = S0 + S1 = 500m. And then s1 + s2 = 500 and solving it from there. A stone is thrown up with an initial velocity of 40m/s.

When a body dropped from a height explodes in mid-air?

When a body dropped from a height explodes in mid-air,its center of mass keeps moving in vertically downward direction. Explosion occur under internal forces only. External is zero. A stone is dropped freely from the top of a tower and it reaches the ground in 4 sec taking (g = 1 0 m s 2 ).

What is the total time taken to reach the highest point?

Here the angle is 90° as the body is thrown vertically upwards. Total Time of flight = {2×40×sin (90°)}/10 = 8 seconds. Putting the values.. This is the time the body will take to reach the highest point. Total time taken by body = 2× time taken to reach highest point =2×4 = 8 seconds. Hope this help.