Table of Contents
- 1 What volume of 63 percent HNO3 has density?
- 2 How do you find the specific gravity of HNO3?
- 3 What is the density of hno3?
- 4 What volume of water should be added to 50 ml of HNO3 having density 1.5 gram per ml and 63.0 by weight to have one molar solution?
- 5 What is the density of concentrated nitric acid?
- 6 What is the molecular weight of 69\% HNO3 in ML?
- 7 How do you prepare a solution of 70\% HNO3?
What volume of 63 percent HNO3 has density?
Concentrated HNO3, is 63\% by weight (density = 1.4 gm/mL).
What will be the molality of a 63\% by mass solution of nitric acid HNO3?
Therefore, molality of the solution will be \[m=1.067mol/kg\].
How do you find the specific gravity of HNO3?
1 Answer
- ρHNO3=1.42⋅1 g/mL=1.42 g/mL.
- msol=mnitric acid+mwater.
- mwater=1420−979.8=440.2 g water.
What is the mass of hno3?
63.01 g/mol
Nitric acid/Molar mass
What is the density of hno3?
1.51 g/cm³
Nitric acid/Density
What is the density of 65\% nitric acid?
1.39 g/cm3
Pricing & Availability
| Physicochemical Information | |
|---|---|
| Boiling point | 121 °C (1013 hPa) |
| Density | 1.39 g/cm3 (20 °C) |
| Melting Point | -32 °C |
| pH value | <1 (H₂O, 20 °C) strongly acid |
What volume of water should be added to 50 ml of HNO3 having density 1.5 gram per ml and 63.0 by weight to have one molar solution?
so, Volume of water required = 750 – 50 = 700 mL. A 63\% by weight solution of HNO3 has a density of 1.5 g/ mL.
What volume of water should be added to 50 ml of HNO3 having density 1.5 gram per ml and 63\% by weight to have one molar solution?
The correct answer to this question is option B, 700 ml water should be added to 50 ml \[HN{{O}_{3}}\] to have a 1M solution.
What is the density of concentrated nitric acid?
1.42 g/mL
The density of concentrated nitric acid is 1.42 g/mL.
What is the density of a concentrated HNO3 solution?
A concentrated HNO3 is 63\% HNO3 by mass, and have a density of 1.4 gram per ml. How many ml of the solution is required to prepare 250 ml of a 1.20 M HNO3? UpdateCancel.
What is the molecular weight of 69\% HNO3 in ML?
Each mL of the acid has a mass of 1.41 gms, 69\% of which is HNO3. That is 0.9729 gms HNO3/ mL. The Molecular weight of HNO3 is 63. Therefore each mL of the 69\% acid contains 0.9729 / 63 = 0.0154 mol which equals 15.4 mol/ liter.
How do you calculate the normality of 69\% HNO3?
First, calculate the normality of 69\% HNO3. Each mL of the acid has a mass of 1.41 gms, 69\% of which is HNO3. That is 0.9729 gms HNO3/ mL. The Molecular weight of HNO3 is 63.
How do you prepare a solution of 70\% HNO3?
70\% HNO3 will contain 700 gm/L of the acid. That’s 700/63 mol/L = 11.1 M HNO3 To prepare the solution, you would carefully mix 45.0 mL of the concentrated acid with 205.0 mL of water. Check: (45.0 x 11.1)/250 = 1.998