What is the geometry of ICl2?
The molecular geometry of ICl2- is linear whereas electron geometry is trigonal bipyramidal.
What is the hybridization of ClO4?
Therefore hybridization of ClO4 is sp3.
How do you find the hybridization of ClO4?
Here, the central atom is chlorine (Cl) which has 7 valence electrons and this Cl atom is linked to 4 atoms of O (divalent atom). The anionic charge on the molecule is clearly -1. Therefore, the hybridization of ${\text{ClO}}_4^ – $ is ${\text{s}}{{\text{p}}^3}$. Hence, option C is correct.
What is the hybridization of iodine in icl2?
Answer: The central iodine atom in triiodide has sp3d hybridization. In triiodide anion the central iodine atom has three equatorial lone pairs of electrons and the terminal iodines are bonded axially in a linear shape. Electrons in sp3d hybridization are arranged in trigonal bipyramidal symmetry.
What is the formula for hybridization?
Hybridization=1/2(valency electron in central atom+no. Of atom attached to central atom by single bond+negative charge-positive charge).
What is the molecular shape of ICl2-?
The ICl 2− has sp 3 d-hybridized structure having trigonal bipyramidal shape but due to the presence of lone pair of electron on iodine atom the structure is distorted. The three lone pairs are in the equatorial positions, leaving the Cl and I in a linear molecular shape.
How many lone pairs are present in ICl2-?
ICL2- contains 2 bond pairs and 3 lonepairs due to more repulsions between lone pair-lone pair, all 3 lone pairs are located in equitorial position and axial line is located with 2 bond pairs of chlorine.
What is the hybridisation of the halogen in ICL?
Locally, for both Cl and I atoms, hybridasation theory then tells us that the best way to account for 3 lone pairs and a single covalent bond is to combine 1 ns orbital and 3 np orbitals, resulting in 4 sp³ hybrids, which assume a tetrahedral geometry. Thus, each of the halogens in the molecule ICl will assume sp³ hybridisation.
What is the hybridization of iodine in sp3?
As it is a positive species the central atom contains 6 electrons, out of which 2 e will be involved in forming two sigma bonds with two chlorine atoms and there will 2 lone pairs. So, iodine has two bonding e pairs and 2 lone e pairs. Therefore, It will be sp3 hybridized.