Sage-Tips

How much below the surface of the earth does the acceleration due to gravity reduced to 36\%?

Answer is 4096 km.

How much below the surface of the earth does the acceleration due to gravity reduced?

Radius of the earth = 6400 km . How much above the surface of the earth does the acceleration due to gravity reduce by 36\% of its value on the surface of the earth.

How much below the surface of the earth does the acceleration due to gravity reduces to 64?

How much above the surface of earth does the accelration due to gravity reduces by 64\% of its value on the earth. Radius of earth = 6400 km.

At what distance below the surface of the earth the acceleration due to gravity decreases by 10?

At distance 640 km below the surface of the Earth, value of acceleration due to gravity decreases by 10\%.

How much below the surface of the earth does the acceleration?

At what depth from the surface of earth, the value of acceleration due to gravity is reduced by 40\% of its value on the surface of earth. Radius of the earth =6.4×106m.

How much below the surface of the earth does the acceleration due to gravity become 1 its value at the earth’s surface radius of Earth 6400 km?

How much below the earth’s surface of the earth does the acceleration due to gravity become 1\% of its value at the earth’s surface? Answer-6336km.

How far away from the surface of earth does the acceleration due to gravity reduced by 64\% of its value on the surface?

But if acceleration due to gravity decreases by 64\%, then remaining is 36\%. Solving in same way as above, we have h = 21.3 × 10^3 KM from surface of earth.

At what distance below the surface of the earth the acceleration due to gravity decreases by 10\% of it’s value at the surface given Radius of the earth is 6400km?

at what distance below the surface of the Earth the acceleration due to gravity decrease by 10\% of its value at the surface given radius of earth is 6400km (ans: 640km)​

How far away from the surface of earth does the acceleration due to gravity become 4\% of its value on the surface of earth?

Therefore, the value of gravitational acceleration will become 4 \% at a distance of 25,600 km from the earth surface.

How much above the surface of earth’s does the acceleration?

How much above the surface of earth does the acceleration due to gravity reduce by 36\% of its value on the surface of earth… Q: How much above the surface of earth does the acceleration due to gravity reduce by 36\% of its value on the surface of earth. Sol: Since g reduces by 36\%, the value of g there is 100-36 = 64\%.

How much below the surface of the earth does the acceleration due to gravity become 70\% of its value on the surface of earth?

Answer Expert Verified Let the depth at which acceleration due to gravity ( g) becomes 70\% or 7g/10 = d. d= 1920 km.

How much below the surface of the earth does the acceleration due to gravity become 70\% of its value at the surface of the earth?

How much below the surface does the acceleration due to gravity increase?

> How much below the surface How much below the surface of the earth does the acceleration due to gravity become 70 \% of its value at the surface of earth? (Take R = 6400km) 1920km below the surface of earth does the acceleration due to gravity become 70\% of its value at the surface of earth.

What is the radius of the Earth in kilometers?

The radius of the Earth is 6400 km. 8 clever moves when you have $1,000 in the bank. We’ve put together a list of 8 money apps to get you on the path towards a bright financial future. Had to do this one on a sketch pad. simplifying we get…………………. Question says Acceleration due to gravity is reduced to 36\% at depth, d. Cheers! Do follow me.

What is the gravity of the Earth at the surface?

Gravity is directly proportional to mass. Assuming uniform density mass would be directly proportional to volume, so the distance at which volume becomes 36\%. Since Earth is spherical for practical purposes volume is (4/3)pi* (r cube). So (r1 cube)/ (r2 cube) should be 0.36. If r2 is 6400kms r1 will be 4552.8234297472 KM’s.

What is the formula for acceleration at the equator?

At poles, θ = 90°⇒ g’ = g. At the equator, θ = 0° ⇒ g′= g – Rω 2. For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface.