Table of Contents
- 1 What will be the molarity of solution containing 4.9 g sulfuric acid in 250 ml of water?
- 2 How do you calculate the molarity of a sulfuric acid solution?
- 3 What is the molarity of sulfuric acid?
- 4 What is the molarity of 49\%?
- 5 What is the mass of 49g of H2SO4 in 1 litre solution?
- 6 What is the concentration of H2SO4 in 250 ml of solvent?
What will be the molarity of solution containing 4.9 g sulfuric acid in 250 ml of water?
Answer: Molarity of sulfuric acid solution is 0.0499 mol/L.
How do you calculate the molarity of a sulfuric acid solution?
1 gram of H2SO4 will be equal to 1/98.08 moles. Therefore, we can say that 1 liter of Sulfuric acid contains 17.822 moles or in other words molarity of 95\% (w/w) Sulfuric acid is equal to 17.822 M….Known values.
| Known values | |
|---|---|
| Molecular weight of H2SO4 | 98.08 g/mole |
| Concentration of Sulfuric acid | 95\% (\% by mass, wt/wt) |
What is the molarity of 2l solution containing 49gm of H3PO4?
= 0.25⋅mol⋅L−1 with respect to H3PO4 .
How is molality of a solution different from its molarity?
An important distinction between molality and molarity is the difference between a solution and a solvent. Molarity is the ratio of the moles of a solute to the total liters of a solution. Molality, on the other hand, is the ratio of the moles of a solute to the kilograms of a solvent.
What is the molarity of sulfuric acid?
Dilutions to Make a 1 Molar Solution
| Concentrated Reagent | Formula Weight1 | Molarity (M) |
|---|---|---|
| Sulfuric Acid (H2SO4) | 98.073 | 18 |
| Ammonium Hydroxide (NH4OH) | 35.046 | 14.5 |
| Sodium Hydroxide (NaOH) | 39.997 | 19.4 |
| Potassium Hydroxide (KOH) | 56.105 | 11.7 |
What is the molarity of 49\%?
– Therefore the molarity of a solution of HCl which contains 49\% by weight of solute and whose specific gravity is 1.41 is 18.92 M. – So, the correct option is C.
How do you find the molarity of an acid solution?
Molarity is a ratio between moles of solute and volume of solution. By dividing the number of moles of HCl by the volume (L) of solution in which it was dissolved, we will obtain the molarity of the acid solution. 2.
What is the molarity of a solution of sulfuric acid and water?
Molarity is defined as number of gram moles per litre of solution. When we make a solution using the question’s data, the volume of the mixture of 49 grams (0.5 gram mole) of sulfuric acid and 250 ml cm3 (ml) of water is about 264 ml = 0.264 litres. ( I used the density tables in Perry BTW).
What is the mass of 49g of H2SO4 in 1 litre solution?
This means 49g of H2SO4 in 1 litre solution is 1N or 4.9g in 100ml solution or 4.9\% solution is 1N. Molecular weight of H2SO4 being double of its equivalent weight (a dibasic acid) 98g in 1 litre solution is 1 molar 9.8\% solution is 1 molar. So 4.9 \% H2SO4 solution in 0.5 molar or 0.5M.
What is the concentration of H2SO4 in 250 ml of solvent?
Molarity is defined as the number of moles of a compound per liter of solvent. The molecular weight of H2SO4 is 98 g/mol and therefore, 49 g represents This is in 250 mL, which is the same as 0.25 L. So, using the definition of molarity the concentration is
What is the molarity of 5\% acetic acid?
So, the 5\% them means: 5 g acetic acid per 100 mL of solution. Now, you need the density of the solution. It is in the units: grams of solution / volume of solution. So suppose they want the molarity of 5\% acetic acid. You need a volume of solution to start. So assume you have 1000 mL of solution.