What is the rate law for the following reaction H2 Br2 → 2HBr?

What is the rate law for the following reaction H2 Br2 → 2HBr?

The rate law is dtdx​=k[H2​]1/2[Br2​]1/2: On increasing the concentration of Br2​ four times, by how much times the rate of reaction will change?

Which type of reaction is this H2 Br2 2HBr?

redox reaction
So, this is a redox reaction.

What happens when H2 reacts with Br2?

The reaction between H2​ and Br2​ to form HBr in the presence of the light is initiated by the photo decomposition of Br2​ into free Br atoms(free radicals) by absorption of light. The bond dissociation energy of Br2​ is 192 KJ/mole.

How do you write the formula for hydrogen bromide?

HBr
Hydrogen bromide/Formula

Which of the following is a redox reaction h2 br2?

The reaction H2 + Br2 → 2HBr is a redox reaction. As H2 has an oxidation state of zero and Br2 also has zero oxidation state. Hence , both oxidation and reduction is taking place simultaneously. It is a redox reaction.

READ ALSO:   How do I fix Windows Defender error?

What is the order of reaction h2 i2 2hi?

The order of the reaction is the exponent in the rate law. Thus, this is a second order reaction.

Why are there 2 HBR molecules in H2 and Br2?

The 2 in H2 and Br2 means there are 2 H atoms, in nature H never exists as a single atom. I think in this case thinking about this visually rather than mathematically helps a lot. The 2 hydrogen atoms get broken up in the reaction and individually bind to each Br atom due to the valence electrons, therefor 2 HBr molecules form.

What does 2 in front of HBr mean in this equation?

It means the same thing. The 2 infront of HBR means that that hole expressions is multiplied by two, so two hydrogens, and two bromines. Instead of writing 2 hydrogens and 2 bromines, you can just right two infront of the whole expression, rendering the equation complete.

What is the balanced equation for the combustion reaction of propene?

READ ALSO:   How does a thermostat on a water heater work?

For the balanced equation: 2C3H6 (g) + 9O2 (g) —> 3CO2 (g) + 3 H2O (g) …? The equation above represents the combustion reaction for propene, the third in the homologous series of alkenes with general molecular formular CnH2n which are more unsaturated compared to their preceding simbling, the alkanes (CnH2n+2).