Table of Contents
Why is h20 bond angle greater than H2S?
Bond angle of H2O is larger because oxygen is more electronegative than sulphur therefore bond pair electron of O–H bond will be closer to oxygen and there will be more bond-pair bond-pair repulsion between bond pairs of two O–H bonds.
Which of the following has lowest bond angle H2S?
See , H2S has the least bond angle among them because in H2S orbitals don’t take part in hybridization. Where as Ch4 has highest bond angle among all of them .
Which bond is present in H2S?
Sulphur has only 6 electrons in its last orbit, hence it requires two more electrons to complete its octet state. Therefore, it shares two electrons with two hydrogen atoms and forms 2 covalent bonds with it.
Which of the following has the least bond angle?
Therefore, water has the least bond angle.
Why does the bond angle increase in H2O?
As we know in both structure two bond pair and two lone pair are present and both has tetrahedral geometry. In H2O, oxygen is more electronegative, electrons of two O-H bonds are more attracted towards oxygen atom. Consequently more bond pair- bond pair repulsion take place,so bond angle get increase
Why does the angle of refraction of oxygen in H2S decrease?
On the other hand in H2S, because of less electronegative character of S,less repulsion is present so angle get decrease. It is because oxygen is more electronegetive than sulphur thus attracts the electron pair towards itself causing more repulsive force to act between the bonds….
Why does the bond angle decrease with electronegativity?
As the electronegativity of the central atom decreases, bond angle decreases. In the present case, S is less electronegative than oxygen. Thus bond pairs in H 2 S are more away from the central atom than in H 2 O and thus repulsive forces between bond pairs are smaller producing smaller bond angle.
Why is the repulsion of oxygen greater in H2O than H2S?
In case of H2O molecule, as oxygen is small in size and has high electronegativity value, the bp are closer due to which it is subjected to larger repulsion (bo-bp). In case of H2 S as S atom is larger than O, bp-bp repulsion is less as compared to H2O and it is true for H2 Se and H2 Te as well.