Table of Contents
How much HCl is needed to neutralize the NaOH?
In the neutralization of hydrochloric acid by sodium hydroxide, the mole ratio of acid to base is 1:1. One mole of HCl would be fully neutralized by one mole of NaOH.
How do you calculate the amount of acid needed to neutralize a base?
Solving an Acid-Base Neutralization Problem
- Step 1: Calculate the number of moles of OH-. Molarity = moles/volume. moles = Molarity x Volume. moles OH- = 0.02 M/100 milliliters.
- Step 2: Calculate the Volume of HCl needed. Molarity = moles/volume. Volume = moles/Molarity. Volume = moles H+/0.075 Molarity.
How much HCl does it take to neutralize NaOH?
To neutralize 0.1 moles of base, you need 0.1 moles of acid. 0.1 moles of HCl is 3.65g of HCl. To account for your acid dilution, you need 3.65/0.15 or 24.3g of 15\% HCl to neutralize 4g of 100\% NaOH.
What is the balanced chemical equation for the neutralization of hydrochloric acid?
The balanced chemical equation representing the neutralization of hydrochloric acid with sodium hydroxide is: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l) + heat. Since theses are dilute solutions and are mostly water, assume that the densities of the solutions and the specific heat capacities of the solutions are approximately 1.0 g/ml
What is the normality of 15\% HCl in 4G NaOH?
Normality of HCl,=150/36.5=4.11 N. No.of Equivalents of NaOH in 4g =4/40= 0.1 N. 0.1 Equivalents of NaOH will be neutralised by 0.1 Equivalents of HCl. So 24.33 ml.of 15\% HCl, will neutralise 4 g of NaOH.
How do you prepare a NaOH solution?
To prepare a 0.01M NaOH solution – Dilute a standardised 0.1 M NaOH solution by a factor of 10. or, Dilute a non standardised 0.1 M NaOH solution by a factor of 10 and then standardise. or, dissolve 0.4 gm NaOH in 1 L of distilled water (a less accurate option also requiring standardisation)