Table of Contents
- 1 How long will it take the ball before it strikes the ground?
- 2 What is the displacement of a ball that is thrown straight up?
- 3 How do you calculate how long a projectile is in the air?
- 4 How do you determine how long a projectile is in the air?
- 5 What is the height of the ball as it rises?
- 6 What is the height of the ball at the top speed?
How long will it take the ball before it strikes the ground?
about 1.1 meters
The ball will travel about 1.1 meters before hitting the ground. Projectile motion problems always have this kind of two-step structure (at least).
What is the displacement of a ball that is thrown straight up?
Thus, the displacement would have to be 0 meters since a ball thrown into the air would come down and the shortest distance is 0. The definition for displacement can also be represented by s=vi(tf−ti)+0.5a(tf−ti)2.
How do you find how long an object is in the air before it lands?
Use the vertical motion model, h = -16t2 + vt + s where v is the initial velocity in feet/second and s is the height in feet to calculate how long the basketball will be in the air for. Round your answer to the nearest tenth.
What is the displacement of the ball?
Displacement is the distance between an object’s initial position and its final position and is usually measured or defined along a straight line. Since this is a calculation that measures distance, the standard unit is the meter (m).
How do you calculate how long a projectile is in the air?
To define the time of flight equation, we should split the formulas into two cases:
- Launching projectile from the ground (initial height = 0)
- t = 2 * V₀ * sin(α) / g.
- Launching projectile from some height (so initial height > 0)
- t = [V₀ * sin(α) + √((V₀ * sin(α))² + 2 * g * h)] / g.
How do you determine how long a projectile is in the air?
To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.
What is the maximum height of a ball thrown vertically upwards?
or H= v1 2/2g (equation of maximum height) ………. (iv) Therefore if a ball is thrown vertically upwards with 98 m/s velocity, the maximum height reached by it would be = (98 x98 )/(2 x 9.8) meter = 490 meter.
Why does the velocity of the ball decrease after the upward throw?
It’s pretty evident that after the upward throw, the velocity of the ball gradually decreases i.e. a negative acceleration was working on the ball. The acceleration is negative because this acceleration is directing downwards while the ball is moving upward.
What is the height of the ball as it rises?
The ball rises to a height of 3.3 m above the ground, or 3.3 m above the y = 0 position. You also have information about velocity at this point. You know that gravity causes an object to slow down as it moves upward and speed up as it moves downward.
What is the height of the ball at the top speed?
However, you know that the ball reaches a maximum height (v y = 0 at the top of the motion) of 3.3 m, so the best relation to select is the one that relates position and velocity. The speed of 6.4 m/s is about 14 mph, so is a reasonable answer.