What is the greatest prime factor of product NT?

What is the greatest prime factor of product NT?

then the greatest prime factor of nt is 5.

What is the prime factorization of a positive integer?

The prime factors of a positive integer are the prime numbers that divide that integer exactly. The process of finding these numbers is called integer factorization, or prime factorization. The fundamental theorem of arithmetic says that every positive integer has a unique prime factorization.

What is the greatest prime factor of 12?

There are overall 6 factors of 12 among which 12 is the biggest factor and its positive factors are 1, 2, 3, 4, 6 and 12. The sum of all factors of 12 is 28. Its Prime Factors are 1, 2, 3, 4, 6, 12 and (1, 12), (2, 6) and (3, 4) are Pair Factors.

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What is the remainder when p is divided by 4?

remainder 3
is divided by 4. it leaves the remainder 3. .

What is 220 as a product of prime factors?

Solution: Since, the prime factors of 220 are 2, 5, 11. Therefore, the product of prime factors = 2 × 5 × 11 = 110.

What is the largest prime factor?

1151
1151 is the largest prime factor !

How do you factor n?

When we write a number n as a product (n = a x b) then say that a and b are factors of n. The equation n = a x b is called a factorization of n. For example, 6 is a factor of 12 because 12 = 2 x 6. Also, 3 is a factor of 6 because 6 = 2 x 3.

What is positive integer factor?

Factors. Factors of a positive integer n are all the positive integers that divide n with remainder equal to zero. For example 2, 3, 4 and 6 are factors of 12 since. 12 ÷ 2 = 6, 12 ÷ 3 = 4, 12 ÷ 4 = 3 and 12 ÷ 6 = 2. These factors are also present when 12 is written as a product of factors (factoring).

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What is the remainder when p is divided by 8?

If p is a positive odd integer, what is the remainder when p is divided by 4? (1) When p is divided by 8, the remainder is 5.