Table of Contents
- 1 How do you find volume of oxygen at STP?
- 2 How do you find volume from moles at STP?
- 3 What will be the volume of O gas at STP which is required for complete combustion of 7.8 g acetylene CH )?
- 4 What is the volume occupied by 0.25 mol of a gas at STP?
- 5 What is the number of moles of O2 at STP?
- 6 How do you find the volume of 1 mole of gas?
How do you find volume of oxygen at STP?
Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .
How do you find volume from moles at STP?
It can be written as: V = nRT/P. “P” is pressure, “V” is volume, n is the number of moles of a gas, “R” is the molar gas constant and “T” is temperature. Record the molar gas constant “R”. R = 8.314472 J/mole x K.
What is the volume of one mole of oxygen at STP?
22.4 L
Finally, use the fact that one mole of oxygen would occupy a volume of 22.4 L at STP to figure out the volume of the oxygen in this question at STP.
What will be the volume of O gas at STP which is required for complete combustion of 7.8 g acetylene CH )?
According to reaction, At STP; 1 mole of acetylene that is 22.4L require moles of oxygen that is ×22.4=56L for complete combustion. 1 moles of acetylene that is 22.4L produce 2 moles that is 2×22.4=44.8L of carbon dioxide.
What is the volume occupied by 0.25 mol of a gas at STP?
0.25 mole of the gas will occupy 224001×0.25 mL=5600 mL. (a) The mass of 5.6 litres fo a certain gas at STP is 12 g. What is the relative molecular mass or molar mass of the gas?
How do you find the volume of a gas at STP?
Using the Ideal Gas Law, you would find the volume of 1 mole of a gas at Standard Temperature and Pressure (STP). STP = 1 atm of pressure and 273 K for temperature P = 1 atm V =??? n = 1 mole R = 0.0821 atm L/mol K K = 273 K.
What is the number of moles of O2 at STP?
This means the number of moles of O2 is 2 22.4 = 0.089 mol. The Ideal Gas Law makes certain assumptions about the gases: that the particles are very tiny and featureless and that there is no force acting between them. If these assumptions are correct, then one mole of any gas will occupy 22.4 L at STP.
How do you find the volume of 1 mole of gas?
Using the Ideal Gas Law, you would find the volume of 1 mole of a gas at Standard Temperature and Pressure (STP). STP = 1 atm of pressure and 273 K for temperature. P = 1 atm.
How many litres of oxygen does 1 mole of oxygen occupy?
At STP, 1 mole of oxygen occupies 22.4 litres. ∴ 0.1 mole of oxygen will occupy = 0.1 × 22.4 = 2.24 litres.