Sage-Tips

What happens to the value of g as we move away from the surface of earth?

Answer: Yes, for both the cases it does change. The value of ‘g’, i.e., acceleration due to gravity does not remain the same on all places of the surface of the earth. It can be easily made out that the value of ‘g’ varies on the basis of altitude.

What is the effect on value of g when we move upward from Earth surface and downward from earth surface?

This is the acceleration due to gravity at a height above the surface of the earth. Observing the above formula we can say that the value of g decreases with increase in height of an object and the value of g becomes zero at infinite distance from the earth.

Why value of g changes if we go inside the earth?

The value of g REDUCES as we go deep inside the earth because the respective spherical mass of earth decreases, that is, the radius of earth decreases, which results in the decrease of mass of earth, as the density of the earth remains same throughout.

Why does g increase as we move from the equator to the pole?

So, as we go from the equator to poles, the value of g increases. Since the distance at the poles is smaller than that of the equator hence we can say that person has more acceleration due to gravity on the poles than the equator. The value of acceleration due to gravity increases as we move from equator to pole.

Why does the value of g increase at the equator?

Earth is not a perfect sphere. It is flattened at the poles and bulged at the equator. The centrifugal force caused by the rotation of the earth results in the bulge of the earth at the equator. Therefore the acceleration due to gravity is greater at the poles than at the equator.

Does the value of g changes from place to place?

The value of G does not change from place to place. It is a universal constant. The gravitational constant is the constant of proportionality in Universal Gravitation law given by Issac Newton and is commonly denoted by ‘G’. This is different from ‘g’, which denotes the acceleration due to gravity.

Does value of g remain constant?

The value of g remains the same at all the places on the earth’s surface. The value of ‘g’ is minimum at the equator on the surface of the earth maximum at the poles. Earth is not a perfect sphere So, the value of ‘g’ varies from place to place.

Why the value of g is smaller at the equator than at the poles?

It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth’s oblateness. The measured value is larger because the earth’s density is not uniform but increases toward the center.

Why does the value of G vary across the earth’s surface?

There are slight variations in the value of g about earth’s surface. These variations result from the varying density of the geologic structures below each specific surface location. They also result from the fact that the earth is not truly spherical; the earth’s surface is further from its center at the equator than it is at the poles.

How does the value of G change as an object moves?

And of course, the value of g will change as an object is moved further from Earth’s center. For instance, if an object were moved to a location that is two earth-radii from the center of the earth – that is, two times 6.38×10 6 m – then a significantly different value of g will be found.

How acceleration due to gravity changes with depth from Earth’s surface?

Variation of g with depth or How Acceleration due to gravity changes with depth from the earth’s surface? As depth h increases below the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g2 = g (1 – h/R). Here g2 is the acceleration due to gravity at depth h and R is the radius of the earth.

Why does the value of ‘G’ decrease as we go deep inside?

Why does the value of ‘g’ decrease as we go deep inside a mine (or the Earth)? depends linearly on r. It decreases as r decreases (deep inside a mine). Was this answer helpful? Find the acceleration due to gravity of the moon at a point 1000km above the moon’s surface.