Table of Contents
What is the gram molecular volume of oxygen at STP?
Hence, gram molecular volume of oxygen gas at STP is $22400{\text{ c}}{{\text{m}}^3}$ and the correct option is (C). Note: The value of pressure, temperature, moles and R should be taken with a proper unit system.
What is the gram molecular volume?
The volume occupied by one gram mole of a substance in the gaseous or is the vapour state at STP is called the gram molecular volume.
What is the value of gram molecular volume at STP?
At Standard Temperature and Pressure 1 mole or gram molecular weight of a substance occupies 22.4 L of volume.
What is molecular gram?
Gram molecular mass is the mass in grams of one mole of a molecular substance. Gram molecular mass is the same as molar mass. Gram molecular mass may be reported in grams or grams per mole (g/mol).
What is the value of oxygen at STP?
Step by step answer: The standard value of temperature and pressure at STP is 273k and 1 atm respectively. At STP volume of gas is 22400 ml. The molecular formula of oxygen gas is O2 . So, at STP the mass of oxygen gas having volume 22400 ml is 32 g.
What is the gram molecular mass of oxygen?
32 g
Gram molecular mass of oxygen is 32 g .
What is the gram molar volume of any gas at STP in Litre?
22.4 litre
At STP, the molar volume of an ideal gas is 22.4 litre.
What is gram molecular volume Class 11?
The gram molecular volume is the volume occupied by one mole of ideal gas at STP. It is equal to 22.4 L.
How do you find the gram molecular mass of oxygen?
The mass of an oxygen atom = 16 amu. ∴ Mass of O2 molecule = 2 × 16 = 32 amu. ⇒ 5.31 × 10-23g.
How do you calculate volume of O2?
Calculate the volume (in cubic meters) of gaseous oxygen using the ideal gas law: multiply the amount of oxygen (in moles) by temperature and the molar gas constant followed by dividing the product by pressure.
What is the volume of 1 mole of oxygen at STP?
At Standard Temperature and Pressure (STP), 1 mole of any gas will occupy a volume of 22.4 L. What is gram molecular volume of oxygen at STP? Hence, gram molecular volume of oxygen gas at STP is 22400 cm3 and the correct option is (C).
What is the gram molecular volume of gas?
The volume occupied by one gram mole of a substance in the gaseous or is the vapour state at STP is called the gram molecular volume. The gram molecular volume of all the substance is found to be 22.4dm3or 22400cm3. The mass in gram of 22.4dm3of a gas or vapour at STP is equal to its gram molecular weight.
What is the gram molecular volume of 22400cm3?
The gram molecular volume of all the substance is found to be 22.4dm3or 22400cm3. The mass in gram of 22.4dm3of a gas or vapour at STP is equal to its gram molecular weight.
How do you find the mass of 8 grams of oxygen?
First and foremost, keeping in mind that at room temperature, Oxygen is a gas. So, Volume of Oxygen (O2) given = 5.6L. Finding moles, Moles=Volume/22.4. Moles= 5.6/22.4=1/4moles. Mass ( in grams) = 1/4 × 32. We have taken 32 as oxygen is is combined state O2, so 16×2=32. We get, mass =8 grams. This is mass not active mass.