Sage-Tips

How many words can be formed such that no two vowels come together?

The total amount of arrangements with no two vowels together is trickier. So, there are 1152 combinations, or 22.9\% of all the combinations.

How many ways the letter of the word Oriental can be arranged if no two vowels come together?

the total arrangements of the letters in the word oriental with the vowel always together is 20*24 equal 2880.

How many arrangements are there where no two vowels are next to each other?

ways. In total we have (63)×3! ×5! =14400 ways.

How many ways can you do this if no vowel is isolated between two consonants?

How many ways can you do this if no vowel is isolated between two consonants? The final answer is given to be 1872.

How many words can be formed using all the word combine?

64 words can be made from the letters in the word combine.

How many different words can be formed of the letter of the word combine so that vowels may occupy odd places?

In order that the vowels may occupy odd places, we first of all arrange any 3 consonants in even places in 4P3 ways and then the odd places can be filled by 3 vowels and the remaining 1 consonant in 4P4 ways. So, Required number of words = 4P3 × 4P4 = 24 × 24 = 576.

How many different words can be formed from combine?

How many different words can be formed of the letters of the word combine so that vowels may occupy odd places?

How many words can be made by using letters of the word combine all at a time?

In all there are 24*6 = 144 ways of arranging the letters. The required number of arrangements that satisfy the condition that vowels and consonants are not together is 144.

How many words can be formed from a bundle of vowels?

(i) Now, all the vowels should come together, so consider the bundle of vowels as one letter, then total letters will be 6. So, the number of words formed by these letters will be 6!

How many consecutive vowels do we subtract from an arrangement?

Thus, we have subtracted each arrangement with two pairs of consecutive vowels (which, in this case, means three consecutive vowels) twice, once when we designate the first two vowels as the pair of consecutive vowels and once when we designate the last two vowels as the pair of consecutive vowels.

How many $ ways can you arrange the vowels in daughter?

Since the eight letters of DAUGHTER are distinct, they can be arranged in $8!$ ways. From these, we must exclude those arrangements in which a pair of vowels is consecutive. A pair of consecutive vowels: There are $\\binom{3}{2}$ ways to choose two of the three vowels to be in the pair.

How many permutations where at least 2 vowels are consecutive $2$?

Let us suppose any two of the vowels be one letter. So, total no. of letters becomes $7$. Again, the vowels will change position among themselves. Therefore, total no of permutation where at least $2$ vowels are consecutive $= 7!.3!$