Table of Contents
- 1 What is the value of M and N respectively if m39048458n is divisible by 8 and 11 where?
- 2 How many 3 digit numbers are there which are divisible by 6?
- 3 Which is a chord but not a diameter?
- 4 Which number will completely divide?
- 5 What are the factors of 7200?
- 6 Is m39048458 divisible by 8 and 11?
- 7 Which number is divisible by 8 if n = 4?
What is the value of M and N respectively if m39048458n is divisible by 8 and 11 where?
A number is divisible by 8 , if the number formed by the last three digits is divisible by 8. Again a number is divisible by 11, if the difference between the sum of digits at even places and sum of digits at the odd places is either 0 or divisible by 11. It cannot be zero hence, M + 5 = 11 ⇒ M=6.
What is the value of M and N respectively if?
Therefore, the value of m and n is 2 and 0, respectively.
How many 3 digit numbers are there which are divisible by 6?
150
The value of n = 6. Thus, the number of 3-digit numbers divisible by 6 is 150.
How many divisors does 7200 have *?
54 factors
Factors of 7200 are integers that can be divided evenly into 7200. It has total 54 factors of which 7200 is the biggest factor and the prime factors of 7200 are 2, 3, 5. The Prime Factorization of 7200 is 25 × 32 × 52.
Which is a chord but not a diameter?
A chord is a line segment that joins two points on a curve. A diameter satisfies the definition of a chord, however, a chord is not necessarily a diameter. This is because every diameter passes through the center of a circle, but some chords do not pass through the center.
Which natural number is nearest to 8485?
Step-by-step explanation: The nearest natural number greater than 8485 which is divisible by 75 is: 114 * 75 = 8550.
Which number will completely divide?
(17200 – 1200) is completely divisible by (17 + 1), i.e., 18. (17200 – 1) is completely divisible by 18. On dividing 17200 by 18, we get 1 as remainder….Exercise :: Numbers – General Questions.
| A. | 250001 |
|---|---|
| B. | 251001 |
| C. | 260101 |
| D. | 261001 |
How many 3 digit multiples of 6 have the sum of digits divisible by 6 if all digits are different?
So, number of 3 digit numbers divisible by 6 is 150. Substitute a = 102, d = 6, l = 996 and n = 150.
What are the factors of 7200?
The factors of 7200 are 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 25, 30, 32, 36, 40, 45, 48, 50, 60, 72, 75, 80, 90, 96, 100, 120, 144, 150, 160, 180, 200, 225, 240, 288, 300, 360, 400, 450, 480, 600, 720, 800, 900, 1200, 1440, 1800, 2400, 3600, 7200 and factors of 513 are 1, 3, 9, 19, 27, 57, 171, 513.
What is the total number of different divisors?
The formula for calculating the total number of divisor of a number ′n′ where n can be represent as powers of prime numbers is shown as. If N=paqbrc . Then total number of divisors =(a+1)(b+1)(c+1).
Is m39048458 divisible by 8 and 11?
Well M39048458N is divisible by 8 and 11. For the number to be divisible 8, the last three digits should be divisible by 8. So N should be 4 for4584 is divisible by 8. So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11.
What is the sum of the even numbers in m390484584?
So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11. The sum of the numbers in the even position is = 3+0+8+5+4 = 20.
Which number is divisible by 8 if n = 4?
Here, last three digits 58N are divisible by 8 if N = 4 because 584 is divisible by 8. Test of Divisibility by 11 If the digits at odd and even places of a given number are equal or differ by a number divisible by 11, then the given number is divisible by 11.
Is 58N divisible by 8?
N can have just one value for 58N to be divible by 8. Incidently if the last three digits were 56N then there would be two possible solutions. If the number is divisible by 8 then it’s last three digits must be divisible by 8. Therefore, 58N must be divisible by 8.